Use the Application object's Context property.
http://www.kinook.com/VisBuildPro/Ma...xtproperty.htm
For instance, within a VBScript
Run Script step:
Code:
If Application.Context = vbldContextGUI Then
Builder.LogMessage "Running in GUI"
ElseIf Application.Context = vbldContextCommandLine Then
Builder.LogMessage "Running in console"
Else
Builder.LogMessage "Running via object model"
End If